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No Higgs particle at all

 It is also possible that there will be no Higgs like particle at all. This would destroy the nice theory giving mass to the vector bosons but would not be in contradiction to any experimental results. Many different theories are available to define such a situation among them the so-called technicolour models. As a first test of a new theory it has to be unitary in the scattering amplitudes (2.93).

Taking the unitarisation instead as a definition, several effective models can be developed where |alI| is kept below unity for all energies [30,31] either by keeping the complex value for higher energies when it reaches |alI| =1, or by redefining the amplitude as

 
alI' = $\displaystyle{\frac{a_l^I}{1-{i}a_l^I}}$. (47)

From an analysis done in just the leptonic decay channel ( W +W - $\rightarrow$ l +$\nu$$
\l 
^{-}_{}$$\nu$) it is in [31] concluded that the different models without any Higgs boson would reveal an excess in the W +W - $\rightarrow$ W +W - scattering with data from one year at high luminosity (100 fb - 1). However, to distinguish between the different models will require much more data.


next up previous contents
Next: Transition radiation detectors Up: Higgs physics at the Previous: A very heavy Higgs mH
Ulrik Egede
1/8/1998