With a fixed detector length, optimisation is required for.
The choice of xenon as the detecting gas is obvious from its short
absorption length as seen in fig. 3.7. With a gas
thickness of around 0.5 cm there is large absorption up to 10 keV. In
the figure is also seen that 4 keV photons have an absorption length
of just 300
m in a typical radiator foil giving only a small
window for detecting transition radiation with
7 keV.
For the foil material where low absorption is important a low Z
material is the best. Since lithium and beryllium are reactive
materials the best practical choices are carbohydrates like
polyethylene or polypropylene. The gas between the foils in the
radiator has to have as low electron density as possible to achieve a
low plasma frequency and thereby limit the saturation effect
(3.25). Helium is this aspect is the best choice with
'max = 26000 while for air
'max = 9600
for a 7 keV photon energy.
With
and the radiator composition fixed the optimal
foil thickness can be calculated from (3.31) and
table 3.1 giving
l1optimal
20
m.
The actual thickness of the foil has then to take into account a
typical crossing angle between the particles and the foil.
| Material | |
|
| polypropylene | 20.87 | 0.935 |
| helium | 0.27 |
0.18 |
| air | 0.73 |
1.29 |
| Kapton | 24.5 | 1.39 |
| xenon | 1.42 |
5.89 |
| Xe/CF4/CO2 | 1.70 |
4.80 |
To perform well for emission angles above
> 0.2 mrad
(fig. 3.2) and for X-rays above 4 keV,
(3.16) gives a minimum spacing of the foils of
l2minimal
1.3 mm with air as the medium between the
foils. For helium the minimum spacing is 2.2 mm.
The effective number of foils can now be calculated from (3.9) and fig. 3.7. The effective number of foils is below 35 for 5 keV X-rays. Hence not much is gained by having Nfoil > 35 .
Adding up the different lengths gives
|
ldet = Nfoil(l1 + l2) + lgas | (68) |
|
n | (69) |
The solution to the problem is to place multiple copies of the radiator and detection gas behind each other. This also opens up the possibility to combine the particle identification with tracking.
To measure the energy deposited as ionisation in the xenon gas there are 2 methods called the Q and the N method.
In the Q method, one measures with ADC's or FADC's the total energy
deposited in the gas which is a sum of the transition radiation in the
radiator and
from the particle which also passes
through the detecting gas. The method is sensitive to background from
the Landau tail of
. Since the Q method is mainly
sensitive to the X-rays with the highest energies, the number of foils
can be enlarged in each layer because the absorption of X-rays in the
radiator is only important for the soft part of the spectrum.
The N method instead, counts the number of clusters in the gas. A
cluster is the volume of the gas where the ionisation from the
electron knocked out by the X-ray photon is deposited. It typically
has a diameter of 1 mm. This method is not very sensitive to
since the main part of the ionisation is
spatially spread out. The background mainly comes from
-electrons which are electrons kicked out of the atomic shells
by the primary particle with an energy high enough to make ionisation
themselves.
While the Q method is expensive to implement for a multilayered detector with separate ADC's for each layer of detecting gas, the N-method can be incorporated in a multilayered detector in an elegant way. A threshold on the deposited energy in a single layer can give a simple yes/no answer if there was a cluster in a given layer. The probability for multiple clusters in a single layer is low and only a few clusters will be lost by just having a binary output. With a fixed probability for a cluster in each layer, particles passing all the layers will have a binomial distribution in the number of layers with a cluster registered.
The N method has to distinguish between two different binomial distributions from pions and electrons respectively for particle identification. The distributions have different average values and for binomial distributions there are no suffering from long Landau tails as with the Q method.
Since the total length of the detector is fixed and the length of each layer given by (3.39) also the number of layers is fixed. However, for the N method what counts is the mean number of clusters in all layers given by
| < ncluster > = Nplayer | (70) |
|
ATR = | (71) |
|
N = | (72) |